How To Create A Dynamic Drop Down List In Php Populated From Mysql Database
I am trying to create a dynamic drop down list using PHP and mysql database. I have written the following code and its giving me the output, but the problem is that its showing dif
Solution 1:
Get rid of the inner foreach loop... it is doing nothing for you and move the start and end select tags outside of the while loop.
$select_query= "Select name from category";
$select_query_run = mysql_query($select_query);
echo"<select name='category'>";
while ($select_query_array= mysql_fetch_array($select_query_run) )
{
echo"<option value='' >".htmlspecialchars($select_query_array["name"])."</option>";
}
echo"</select>";
Solution 2:
take look at this code.
$select_query= "Select name from category";
$select_query_run = mysql_query($select_query);
echo"<select>";
while ($select_query_array= mysql_fetch_array($select_query_run) )
{
echo"<option value='' >".$select_query_array['name']."</option>";
}
echo"</select>";
Solution 3:
<?php$res = mysqli_query($conn, "SELECT DISTINCT coloumn_name FROM table_name;" );
while($row = mysqli_fetch_array($res))
{
echo"<option value='" . $row['selected_coloumn']. "'>" . $row['selected_coloumn'] . "</option>";
}
?>
In this example please select your 'coloumn_name'
and 'table_name'
.
Solution 4:
$select_query= "Select name from category";
$select_query_run = mysql_query($select_query);
$selectTag = "<select>";
while ($select_query_array= mysql_fetch_array($select_query_run) ){
foreach ($select_query_arrayas$select_query_display){
$selectTag .="<option value='' >$select_query_display</option>";
}
}
$selectTag .= "</select>";
echo$selectTag;
Solution 5:
You may try it
$select_query= "Select name from category";
$select_query_run = mysql_query($select_query);
$select_query_array= mysql_fetch_array($select_query_run)
$select = "<select>";
foreach ($select_query_arrayas$val)
{
$select .= "<option value='".$val['name']."' >".$val['name']."</option>";
}
$select = "</select>";
echo$select;
Hope It will work
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